| Summary: | 碩士 === 高雄師範大學 === 化學系 === 98 === Abstract:We as human beings have had a history of putting our attention and priorities on the development of technologies and economies. At the meantime, we have neglected the impact brought by this development, which is the prolong pollution that has deeply affected the environment. The wastewater disposal from the dyeing and finishing industry is one of the sources of pollutions. If the wastewater is not appropriately treated prior to its discharge, it would cause effects such as the increase in chromaticity, the change in pH, the escalation in biochemical oxygen demand, the emergence of odor, and the obstruction to the growth of aquatic lives. The Fenton has advantages such as fast reaction, low cost, and effective removal of chromaticity, over other wastewater treatment methods for the dyeing and finishing industry. Therefore, this research takes Red MX-5B as the primary subject to discuss the feasibility of the Fenton. It studies the effects of the variables in the Fenton reagent, such as the concentrations of ferric ion, hydrogen peroxide, sulfuric acid, and temperature, on the reactions.
The conclusions obtained from the experiments are as follows:
(1) It is feasible to use the Fenton reagent on Red MX-5B.
(2) The effect of dye concentration to the Fenton reaction is first order.
(3) The effect of ferric ion concentration to the Fenton reaction is first order. The higher the ferric ion concentration, the faster the reaction, and the more effective the decoloration.
(4) The effects of hydrogen peroxide and sulfuric acid concentrations to the Fenton reaction are both negative first order. Therefore, the lower the concentrations, the faster the reaction, and the more effective the decoloration.
(5) The higher the temperature, the more effective the decoloration.
(6) The ferrous ion is more effective than the ferrous ion in decoloration process, and the higher the concentration, the faster the reaction.
(7) The best conditions in processing 3.0×10-5M Red MX-5B dye are:
[Fe3+]=4.0×10-4M [H2O2]=5.0×10-2M
[H2SO4]=2.0×10-3M Temperature=299.15K
(8) The formulae for Reaction Rate：
Rate＝0.00125×[Fe3+] × 1 × 1 [dye]
[H2O2]+0.4282 [H2SO4]
(9) The rate determining step in the reaction mechanism could be judging from the reaction activation energy：
ＯＨ˙＋MX-5B → ＯＨ˙……MX-5B
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