A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process

碩士 === 淡江大學 === 水資源及環境工程學系 === 84 === This study aims to treat dairy wastewater with laboratory scalecomplete-mixed activated sludge reactors, adopting three different sets ofexperiment, (1)continuous method: a conventional activated sludge...

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Main Authors: Kuo, Hsin-Te, 郭信德
Other Authors: Hsu Ting-Chi
Format: Others
Language:zh-TW
Published: 1996
Online Access:http://ndltd.ncl.edu.tw/handle/80364378703040921009
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spelling ndltd-TW-084TKU000880222015-10-13T17:49:29Z http://ndltd.ncl.edu.tw/handle/80364378703040921009 A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process 非連續進流式活性污泥法處理食品廢水之研究 Kuo, Hsin-Te 郭信德 碩士 淡江大學 水資源及環境工程學系 84 This study aims to treat dairy wastewater with laboratory scalecomplete-mixed activated sludge reactors, adopting three different sets ofexperiment, (1)continuous method: a conventional activated sludge system withcontinuous influent and aeration for 24 hours. (2)method 1: the same systembut stops influenting for 8 after influenting for 16 hours. The aeration neverstops during the 24 hours. (3)method 2: the same system but stops influentingfor 8 hours after influenting for 16 hours. The aeration stops for 8 hours atthe same time.Through these three experiments, this study intends to explorethe change of the organic carbon removal efficiency and biological activitywhen method 1 and method 2, the non- continuous flow methods are operated underthe F/M ratio 0.12-0.38 day-1. The conclusions are as follows:1. The organiccarbon removal efficiency, the average removal efficiency of continuous methodin BOD is 96.1%, COD is 94.6% and SS is 94.1%. The average removal efficiencyof methed 1 in BOD is 95.3%, COD is 93% and SS is 94.3%. The average removalefficiency of method 2 in BOD is 94.5%, COD is 91.7% and SS is 95.2%. thesethree sets of operating methods all produce a nice effect.2. On the biologicalactivity, the SOUR in continuous method is between 3.49 and 6.7 mg O2/gMLVSS- hr, the SOUR in method 1 is between 3.09 and 5.03 mg O2/g MLVSS-hr andthe SOUR in method 2 is between 3.79 and 7.46 mg O2/g MLVSS-hr. The treatmentof method 2 shows higher biological activity.3. On activated sludge produced,the average of daily sludge produced of continuous method is 3.201 Kg, ofmethod 1 2.032 Kg and of method 2 1.874 Kg. Therefore, with method 2 lesssludge is produced. Continuous method produces a larger amount of sludge andaeration. Althrough method 1 produces less sludge than continuous way, theaeration isn''t spared less. By comparison, method 2 can not only produces lesssludge produced, but also saves 8 hours of aeration power. Under an niceorganic carbon removal efficiency, to save power during an operation of 24hours, stopping both the influent and the aeration for 8 hours will be abetter operation way.4. The biological kinetic contants of activated sludgesystems for treating dairy wastewater with three activated sludge systems aresubstrate removal rate constant K(L/mg-day)、 parameters for biomass yieldYt(mg MLVSS/mg substrate Removal) and Kd(1/ day)、oxygen utilization parametersa''(mg O2/mg substrate Removal) and b''(mg O2/mg MLVSS-day) as follows:(1) continuous method: (TCOD basis)K=0.013, Yt=0.384, Kd=0.049, a''=0.012,b''=0.0008。(SCOD basis)K=0.013,Yt=0.492,Kd=0.016, a''=0.015,b''=0.0019。(TBODbasis)K=0.018, Yt=0.510,Kd=0.033, a''=0.016,b''=0.0012。(SBOD basis)K=0.024,Yt=0.738, Kd=0.039, a''=0.023, b''=0.0011。 (2)method 1: (TCOD basis)K=0.008, Yt=0.344, Kd=0.03, a''=0.01, b''=0.0018。 (SCOD basis) K=0.009, Yt=0.378,Kd=0.0002, a''=0.014,b''=0.0023。 (TBOD basis)K=0.012, Yt=0.425, Kd=0.016,a''=0.012, b''=0.0023。 (SBOD basis)K=0.014, Yt=0.655, Kd=0.021, a''=0.017,b''=0.0023 。 (3)method 2: (TCOD basis)K=0.007,Yt=0.296,Kd=0.019, a''=0.016,b''=0.0017。 (SCOD basis) K=0.011, Yt=0.412, Kd=0.008, a''=0.024,b''=0.002。(TBOD basis) K=0.012, Yt=0.407 , Kd=0.013, a''=0.022, b''=0.002。 (SBODbasis)K=0.018, Yt=0.593,Kd=0.016,a''=0.031,b''=0.002。 Hsu Ting-Chi 徐錠基 1996 學位論文 ; thesis 81 zh-TW
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language zh-TW
format Others
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author2 Hsu Ting-Chi
author_facet Hsu Ting-Chi
Kuo, Hsin-Te
郭信德
author Kuo, Hsin-Te
郭信德
spellingShingle Kuo, Hsin-Te
郭信德
A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
author_sort Kuo, Hsin-Te
title A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
title_short A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
title_full A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
title_fullStr A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
title_full_unstemmed A Study on the Treatment of Dairy Wastewater by Non-continuous Flow Activated Sludge Process
title_sort study on the treatment of dairy wastewater by non-continuous flow activated sludge process
publishDate 1996
url http://ndltd.ncl.edu.tw/handle/80364378703040921009
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description 碩士 === 淡江大學 === 水資源及環境工程學系 === 84 === This study aims to treat dairy wastewater with laboratory scalecomplete-mixed activated sludge reactors, adopting three different sets ofexperiment, (1)continuous method: a conventional activated sludge system withcontinuous influent and aeration for 24 hours. (2)method 1: the same systembut stops influenting for 8 after influenting for 16 hours. The aeration neverstops during the 24 hours. (3)method 2: the same system but stops influentingfor 8 hours after influenting for 16 hours. The aeration stops for 8 hours atthe same time.Through these three experiments, this study intends to explorethe change of the organic carbon removal efficiency and biological activitywhen method 1 and method 2, the non- continuous flow methods are operated underthe F/M ratio 0.12-0.38 day-1. The conclusions are as follows:1. The organiccarbon removal efficiency, the average removal efficiency of continuous methodin BOD is 96.1%, COD is 94.6% and SS is 94.1%. The average removal efficiencyof methed 1 in BOD is 95.3%, COD is 93% and SS is 94.3%. The average removalefficiency of method 2 in BOD is 94.5%, COD is 91.7% and SS is 95.2%. thesethree sets of operating methods all produce a nice effect.2. On the biologicalactivity, the SOUR in continuous method is between 3.49 and 6.7 mg O2/gMLVSS- hr, the SOUR in method 1 is between 3.09 and 5.03 mg O2/g MLVSS-hr andthe SOUR in method 2 is between 3.79 and 7.46 mg O2/g MLVSS-hr. The treatmentof method 2 shows higher biological activity.3. On activated sludge produced,the average of daily sludge produced of continuous method is 3.201 Kg, ofmethod 1 2.032 Kg and of method 2 1.874 Kg. Therefore, with method 2 lesssludge is produced. Continuous method produces a larger amount of sludge andaeration. Althrough method 1 produces less sludge than continuous way, theaeration isn''t spared less. By comparison, method 2 can not only produces lesssludge produced, but also saves 8 hours of aeration power. Under an niceorganic carbon removal efficiency, to save power during an operation of 24hours, stopping both the influent and the aeration for 8 hours will be abetter operation way.4. The biological kinetic contants of activated sludgesystems for treating dairy wastewater with three activated sludge systems aresubstrate removal rate constant K(L/mg-day)、 parameters for biomass yieldYt(mg MLVSS/mg substrate Removal) and Kd(1/ day)、oxygen utilization parametersa''(mg O2/mg substrate Removal) and b''(mg O2/mg MLVSS-day) as follows:(1) continuous method: (TCOD basis)K=0.013, Yt=0.384, Kd=0.049, a''=0.012,b''=0.0008。(SCOD basis)K=0.013,Yt=0.492,Kd=0.016, a''=0.015,b''=0.0019。(TBODbasis)K=0.018, Yt=0.510,Kd=0.033, a''=0.016,b''=0.0012。(SBOD basis)K=0.024,Yt=0.738, Kd=0.039, a''=0.023, b''=0.0011。 (2)method 1: (TCOD basis)K=0.008, Yt=0.344, Kd=0.03, a''=0.01, b''=0.0018。 (SCOD basis) K=0.009, Yt=0.378,Kd=0.0002, a''=0.014,b''=0.0023。 (TBOD basis)K=0.012, Yt=0.425, Kd=0.016,a''=0.012, b''=0.0023。 (SBOD basis)K=0.014, Yt=0.655, Kd=0.021, a''=0.017,b''=0.0023 。 (3)method 2: (TCOD basis)K=0.007,Yt=0.296,Kd=0.019, a''=0.016,b''=0.0017。 (SCOD basis) K=0.011, Yt=0.412, Kd=0.008, a''=0.024,b''=0.002。(TBOD basis) K=0.012, Yt=0.407 , Kd=0.013, a''=0.022, b''=0.002。 (SBODbasis)K=0.018, Yt=0.593,Kd=0.016,a''=0.031,b''=0.002。