Distributional, differential and integral problems: equivalence and existence results
We are interested in studying the matter of equivalence of the following problems: \[ \begin{aligned} Dx&=f(t,x)Dg\nonumber \\ x(0)&=x_0 \end{aligned}\tag{1} \label{1a} \] where $Dx$ and $Dg$ stand for the distributional derivatives of $x$ and $g$, respectively; \[ \begin{aligned} x'...
Main Authors: | , |
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Format: | Article |
Language: | English |
Published: |
University of Szeged
2017-01-01
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Series: | Electronic Journal of Qualitative Theory of Differential Equations |
Subjects: | |
Online Access: | http://www.math.u-szeged.hu/ejqtde/periodica.html?periodica=1¶mtipus_ertek=publication¶m_ertek=4753 |
Summary: | We are interested in studying the matter of equivalence of the following problems:
\[
\begin{aligned}
Dx&=f(t,x)Dg\nonumber \\
x(0)&=x_0
\end{aligned}\tag{1} \label{1a}
\]
where $Dx$ and $Dg$ stand for the distributional derivatives of $x$ and $g$, respectively;
\[
\begin{aligned}
x'_g(t)&=f(t,x(t)), \quad m_g\textrm{-a.e.}\\
x(0)&=x_0
\end{aligned}\tag{2}\label{2}
\]
where $x'_g$ denotes the $g$-derivative of $x$ (in a sense to be specified in Section 2) and $m_g$ is the variational measure induced by $g$; and
\begin{equation}\tag{3}\label{3}
x(t)=x_0+\int_0^t f(s,x(s))dg(s),
\end{equation}
where the integral is understood in the Kurzweil--Stieltjes sense.
We prove that, for regulated functions $g$, \eqref{1a} and \eqref{3} are equivalent if $f$ satisfies a bounded variation assumption. The relation between problems \eqref{2} and \eqref{3} is described for very general $f$, though, more restrictive assumptions over the function $g$ are required. We provide then two existence results for the integral problem \eqref{3} and, using the correspondences established with the other problems, we deduce the existence of solutions for \eqref{1a} and \eqref{2}. |
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ISSN: | 1417-3875 1417-3875 |