Ni3Te2O2(PO4)2(OH)4, an open-framework structure isotypic with Co3Te2O2(PO4)2(OH)4

• Main Authors: Felix Eder, Matthias Weil
• Format: Article
• Language: English
• Published: International Union of Crystallography 2020-05-01
• Series: Acta Crystallographica Section E: Crystallographic Communications
• Subjects: crystal structure; oxidotellurate(iv); phosphate; framework structure; isotypism; structure comparison
• Online Access: http://scripts.iucr.org/cgi-bin/paper?S2056989020004466

Single crystals of Ni3(TeO(OH)2)2(PO4)2, trinickel(II) bis[(oxidodihydoxidotellurate(IV)] bis(phosphate),were obtained by hydrothermal synthesis at 483 K, starting from NiCO3·2Ni(OH)2, TeO2 and H3PO4 in a molar ratio of 1:2:2. The crystal structure of Ni3Te2O2(PO4)2(OH)4 is isotypic with that of Co3Te2O2(PO4)2(OH)4 [Zimmermann et al. (2011). J. Solid State Chem. 184, 3080–3084]. The asymmetric unit comprises two Ni (site symmetries \overline{1}, 2/m) one Te (m), one P (m), five O (three m, two 1) and one H (1) sites. The tellurium(IV) atom shows a coordination number of five, with the corresponding [TeO3(OH)2] polyhedron having a distorted square-pyramidal shape. The two NiII atoms are both octahedrally coordinated but form different structural elements: one constitutes chains made up from edge-sharing [NiO6] octahedra extending parallel to [010], and the other isolated [NiO2(OH)4] octahedra. The two kinds of nickel/oxygen octahedra are connected by the [TeO3(OH)2] pyramids and the [PO4] tetrahedra through edge- and corner-sharing into a three-dimensional framework structure with channels extending parallel to [010]. Hydrogen bonds of medium strength between the hydroxy groups and one of the phosphate O atoms consolidate the packing. A quantitative structure comparison between Ni3Te2O2(PO4)2(OH)4 and Co3Te2O2(PO4)2(OH)4 is made.