One-loop free energy of tensionless type IIB string in AdS5×S5
Abstract Considering the zero ’t Hooft coupling limit of N = 4 $$ \mathcal{N}=4 $$ super-Yang-Mills theory, the exact spectrum of all single-trace operators can be accessed in terms of the underlying so(2, 4) character. This makes it possible in turn to compute the one-loop free energy of the tensio...
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doaj-46e9d856bf49428caf7a97dd67bd17512020-11-25T01:40:29ZengSpringerOpenJournal of High Energy Physics1029-84792017-06-012017611610.1007/JHEP06(2017)155One-loop free energy of tensionless type IIB string in AdS5×S5Jin-Beom Bae0Euihun Joung1Shailesh Lal2Korea Institute for Advanced StudyDepartment of Physics and Research Institute of Basic Science, Kyung Hee UniversityLPTHE — UMR 7589, UPMC Paris 06, Sorbonne UniversitésAbstract Considering the zero ’t Hooft coupling limit of N = 4 $$ \mathcal{N}=4 $$ super-Yang-Mills theory, the exact spectrum of all single-trace operators can be accessed in terms of the underlying so(2, 4) character. This makes it possible in turn to compute the one-loop free energy of the tensionless type IIB string theory in AdS5×S5 background, with help of the recently developed method of character integral representation of zeta function (CIRZ). We calcu-late first the one-loop free energy of the string states in the (p − 1)-th Regge trajectory and find the result to be p times the free energy of a single N = 4 $$ \mathcal{N}=4 $$ Maxwell multiplet. The full one-loop free energy is hence proportional to the divergent series ∑ p = 2 ∞ p $$ {\displaystyle {\sum}_{p=2}^{{}_{\infty }}p} $$ . The divergence arises as a result of interrupting the regularization procedure in an intermediate stage. With a reorganization of states, we extract the finite part of free energy after summing over the Regge trajectories. This way gives us a finite result which is minus of the free energy of the N = 4 $$ \mathcal{N}=4 $$ multiplet. Hence, this bulk one-loop result matches the −1 term in the N 2 − 1 factor of the boundary result.http://link.springer.com/article/10.1007/JHEP06(2017)1551/N ExpansionAdS-CFT CorrespondenceHigher Spin GravityHigher Spin Symmetry |
collection |
DOAJ |
language |
English |
format |
Article |
sources |
DOAJ |
author |
Jin-Beom Bae Euihun Joung Shailesh Lal |
spellingShingle |
Jin-Beom Bae Euihun Joung Shailesh Lal One-loop free energy of tensionless type IIB string in AdS5×S5 Journal of High Energy Physics 1/N Expansion AdS-CFT Correspondence Higher Spin Gravity Higher Spin Symmetry |
author_facet |
Jin-Beom Bae Euihun Joung Shailesh Lal |
author_sort |
Jin-Beom Bae |
title |
One-loop free energy of tensionless type IIB string in AdS5×S5 |
title_short |
One-loop free energy of tensionless type IIB string in AdS5×S5 |
title_full |
One-loop free energy of tensionless type IIB string in AdS5×S5 |
title_fullStr |
One-loop free energy of tensionless type IIB string in AdS5×S5 |
title_full_unstemmed |
One-loop free energy of tensionless type IIB string in AdS5×S5 |
title_sort |
one-loop free energy of tensionless type iib string in ads5×s5 |
publisher |
SpringerOpen |
series |
Journal of High Energy Physics |
issn |
1029-8479 |
publishDate |
2017-06-01 |
description |
Abstract Considering the zero ’t Hooft coupling limit of N = 4 $$ \mathcal{N}=4 $$ super-Yang-Mills theory, the exact spectrum of all single-trace operators can be accessed in terms of the underlying so(2, 4) character. This makes it possible in turn to compute the one-loop free energy of the tensionless type IIB string theory in AdS5×S5 background, with help of the recently developed method of character integral representation of zeta function (CIRZ). We calcu-late first the one-loop free energy of the string states in the (p − 1)-th Regge trajectory and find the result to be p times the free energy of a single N = 4 $$ \mathcal{N}=4 $$ Maxwell multiplet. The full one-loop free energy is hence proportional to the divergent series ∑ p = 2 ∞ p $$ {\displaystyle {\sum}_{p=2}^{{}_{\infty }}p} $$ . The divergence arises as a result of interrupting the regularization procedure in an intermediate stage. With a reorganization of states, we extract the finite part of free energy after summing over the Regge trajectories. This way gives us a finite result which is minus of the free energy of the N = 4 $$ \mathcal{N}=4 $$ multiplet. Hence, this bulk one-loop result matches the −1 term in the N 2 − 1 factor of the boundary result. |
topic |
1/N Expansion AdS-CFT Correspondence Higher Spin Gravity Higher Spin Symmetry |
url |
http://link.springer.com/article/10.1007/JHEP06(2017)155 |
work_keys_str_mv |
AT jinbeombae oneloopfreeenergyoftensionlesstypeiibstringinads5s5 AT euihunjoung oneloopfreeenergyoftensionlesstypeiibstringinads5s5 AT shaileshlal oneloopfreeenergyoftensionlesstypeiibstringinads5s5 |
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1725045447886635008 |