Does a Functional Integral Really Need a Lagrangian?

<p>Path integral formulation of quantum mechanics (and also other equivalent formulations) depends on a Lagrangian and/or Hamiltonian function that is chosen to describe the underlying classical system. The arbitrariness presented in this choice leads to a phenomenon called Quantization ambigu...

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Main Author: D. Kochan
Format: Article
Language:English
Published: CTU Central Library 2010-01-01
Series:Acta Polytechnica
Subjects:
Online Access:https://ojs.cvut.cz/ojs/index.php/ap/article/view/1269
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spelling doaj-27d92aa6555f4b2eabd2390bad3c8ccb2020-11-24T22:21:02ZengCTU Central LibraryActa Polytechnica1210-27091805-23632010-01-015051269Does a Functional Integral Really Need a Lagrangian?D. Kochan<p>Path integral formulation of quantum mechanics (and also other equivalent formulations) depends on a Lagrangian and/or Hamiltonian function that is chosen to describe the underlying classical system. The arbitrariness presented in this choice leads to a phenomenon called Quantization ambiguity. For example both L<sub>1</sub> = ˙q<sup>2</sup> and L<sub>2</sub> = e<sup>q</sup>˙ are suitable Lagrangians on a classical level (δL<sub>1</sub> = δL<sub>2</sub>), but quantum mechanically they are diverse.</p> This paper presents a simple rearrangement of the path integral to a surface functional integral. It is shown that the surface functional integral formulation gives transition probability amplitude which is free of any Lagrangian/Hamiltonian and requires just the underlying classical equations of motion. A simple example examining the functionality of the proposed method is considered.https://ojs.cvut.cz/ojs/index.php/ap/article/view/1269quantization of (non-)Lagrangian systemspath vs. surface functional integral
collection DOAJ
language English
format Article
sources DOAJ
author D. Kochan
spellingShingle D. Kochan
Does a Functional Integral Really Need a Lagrangian?
Acta Polytechnica
quantization of (non-)Lagrangian systems
path vs. surface functional integral
author_facet D. Kochan
author_sort D. Kochan
title Does a Functional Integral Really Need a Lagrangian?
title_short Does a Functional Integral Really Need a Lagrangian?
title_full Does a Functional Integral Really Need a Lagrangian?
title_fullStr Does a Functional Integral Really Need a Lagrangian?
title_full_unstemmed Does a Functional Integral Really Need a Lagrangian?
title_sort does a functional integral really need a lagrangian?
publisher CTU Central Library
series Acta Polytechnica
issn 1210-2709
1805-2363
publishDate 2010-01-01
description <p>Path integral formulation of quantum mechanics (and also other equivalent formulations) depends on a Lagrangian and/or Hamiltonian function that is chosen to describe the underlying classical system. The arbitrariness presented in this choice leads to a phenomenon called Quantization ambiguity. For example both L<sub>1</sub> = ˙q<sup>2</sup> and L<sub>2</sub> = e<sup>q</sup>˙ are suitable Lagrangians on a classical level (δL<sub>1</sub> = δL<sub>2</sub>), but quantum mechanically they are diverse.</p> This paper presents a simple rearrangement of the path integral to a surface functional integral. It is shown that the surface functional integral formulation gives transition probability amplitude which is free of any Lagrangian/Hamiltonian and requires just the underlying classical equations of motion. A simple example examining the functionality of the proposed method is considered.
topic quantization of (non-)Lagrangian systems
path vs. surface functional integral
url https://ojs.cvut.cz/ojs/index.php/ap/article/view/1269
work_keys_str_mv AT dkochan doesafunctionalintegralreallyneedalagrangian
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