Melting and freezing in a finite slab due to a linearly decreasing free-stream temperature of a convective boundary condition

• Main Authors: Roday Anand P., Kazmierczak Michael J.
• Format: Article
• Language: English
• Published: VINCA Institute of Nuclear Sciences 2009-01-01
• Series: Thermal Science
• Subjects: finite slab; melting; freezing; heat balance integral; time-dependent; convection
• Online Access: http://www.doiserbia.nb.rs/img/doi/0354-9836/2009/0354-98360902141R.pdf
• ISSN: 0354-9836; 2334-7163

One-dimensional melting and freezing problem in a finite slab with time-dependent convective boundary condition is solved using the heat-balance integral method. The temperature, T4 1(t), is applied at the left face and decreases linearly with time while the other face of the slab is imposed with a constant convective boundary condition where T4 2 is held at a fixed temperature. In this study, the initial condition of the solid is subcooled (initial temperature is below the melting point). The temperature, T4 1(t) at time t = 0 is so chosen such that convective heating takes place and eventually the slab begins to melt (i. e., T4 1(0) > Tf > T4 2). The transient heat conduction problem, until the phase-change starts, is also solved using the heat-balance integral method. Once phase-change process starts, the solid-liquid interface is found to proceed to the right. As time continues, and T4,1(t) decreases with time, the phase-change front slows, stops, and may even reverse direction. Hence this problem features sequential melting and freezing of the slab with partial penetration of the solid-liquid front before reversal of the phase-change process. The effect of varying the Biot number at the right face of the slab is investigated to determine its impact on the growth/recession of the solid-liquid interface. Temperature profiles in solid and liquid regions for the different cases are reported in detail. One of the results for Biot number, Bi2=1.5 are also compared with those obtained by having a constant value of T4 1(t).